Base | Representation |
---|---|
bin | 110000100000001001100010… |
… | …111100000101111110001111 |
3 | 1000222021202121100122220122011 |
4 | 300200021202330011332033 |
5 | 210424430123421042112 |
6 | 2033403442423002051 |
7 | 62634352041651166 |
oct | 6040114274057617 |
9 | 1028252540586564 |
10 | 213315505643407 |
11 | 61a726638a2772 |
12 | 1bb11b83299327 |
13 | 92047482a190b |
14 | 3a967501d63dd |
15 | 199dc5c2c9aa7 |
hex | c20262f05f8f |
213315505643407 has 2 divisors, whose sum is σ = 213315505643408. Its totient is φ = 213315505643406.
The previous prime is 213315505643329. The next prime is 213315505643431. The reversal of 213315505643407 is 704346505513312.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-213315505643407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213315505647407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106657752821703 + 106657752821704.
It is an arithmetic number, because the mean of its divisors is an integer number (106657752821704).
Almost surely, 2213315505643407 is an apocalyptic number.
213315505643407 is a deficient number, since it is larger than the sum of its proper divisors (1).
213315505643407 is an equidigital number, since it uses as much as digits as its factorization.
213315505643407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536000, while the sum is 49.
The spelling of 213315505643407 in words is "two hundred thirteen trillion, three hundred fifteen billion, five hundred five million, six hundred forty-three thousand, four hundred seven".
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