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213330112013 is a prime number
BaseRepresentation
bin1100011010101101110…
…1110010111000001101
3202101122100020112111202
43012223131302320031
511443400002041023
6242000312355245
721261343014224
oct3065335627015
9671570215452
10213330112013
11825223176a7
12354179a5b25
1317169c02915
14a47a61bcbb
155838882128
hex31ab772e0d

213330112013 has 2 divisors, whose sum is σ = 213330112014. Its totient is φ = 213330112012.

The previous prime is 213330111997. The next prime is 213330112031. The reversal of 213330112013 is 310211033312.

Together with next prime (213330112031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128624084164 + 84706027849 = 358642^2 + 291043^2 .

It is a cyclic number.

It is not a de Polignac number, because 213330112013 - 24 = 213330111997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213330112043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106665056006 + 106665056007.

It is an arithmetic number, because the mean of its divisors is an integer number (106665056007).

Almost surely, 2213330112013 is an apocalyptic number.

It is an amenable number.

213330112013 is a deficient number, since it is larger than the sum of its proper divisors (1).

213330112013 is an equidigital number, since it uses as much as digits as its factorization.

213330112013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 213330112013 its reverse (310211033312), we get a palindrome (523541145325).

The spelling of 213330112013 in words is "two hundred thirteen billion, three hundred thirty million, one hundred twelve thousand, thirteen".