Base | Representation |
---|---|
bin | 11111000010110101110… |
… | …000010110100000100001 |
3 | 21112221120001021202020112 |
4 | 133002311300112200201 |
5 | 234423101400130032 |
6 | 4312014321221105 |
7 | 310062323256464 |
oct | 37026560264041 |
9 | 7487501252215 |
10 | 2133353130017 |
11 | 75282825314a |
12 | 2a555b791795 |
13 | 1262360311b5 |
14 | 7537d4052db |
15 | 3a7603db1b2 |
hex | 1f0b5c16821 |
2133353130017 has 2 divisors, whose sum is σ = 2133353130018. Its totient is φ = 2133353130016.
The previous prime is 2133353129981. The next prime is 2133353130037. The reversal of 2133353130017 is 7100313533312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2126606807521 + 6746322496 = 1458289^2 + 82136^2 .
It is a cyclic number.
It is not a de Polignac number, because 2133353130017 - 212 = 2133353125921 is a prime.
It is not a weakly prime, because it can be changed into another prime (2133353130037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066676565008 + 1066676565009.
It is an arithmetic number, because the mean of its divisors is an integer number (1066676565009).
Almost surely, 22133353130017 is an apocalyptic number.
It is an amenable number.
2133353130017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2133353130017 is an equidigital number, since it uses as much as digits as its factorization.
2133353130017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17010, while the sum is 32.
Adding to 2133353130017 its reverse (7100313533312), we get a palindrome (9233666663329).
The spelling of 2133353130017 in words is "two trillion, one hundred thirty-three billion, three hundred fifty-three million, one hundred thirty thousand, seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.107 sec. • engine limits •