Base | Representation |
---|---|
bin | 10011110111100101… |
… | …000001000010101011 |
3 | 2001001202211101021011 |
4 | 103313211001002223 |
5 | 322142341421011 |
6 | 13444523524351 |
7 | 1353444066403 |
oct | 236745010253 |
9 | 61052741234 |
10 | 21333545131 |
11 | 9058259238 |
12 | 41746896b7 |
13 | 201ca593b2 |
14 | 1065459803 |
15 | 84cd85621 |
hex | 4f79410ab |
21333545131 has 2 divisors, whose sum is σ = 21333545132. Its totient is φ = 21333545130.
The previous prime is 21333545087. The next prime is 21333545141. The reversal of 21333545131 is 13154533312.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21333545131 is a prime.
It is a super-2 number, since 2×213335451312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21333545093 and 21333545102.
It is not a weakly prime, because it can be changed into another prime (21333545141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10666772565 + 10666772566.
It is an arithmetic number, because the mean of its divisors is an integer number (10666772566).
Almost surely, 221333545131 is an apocalyptic number.
21333545131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21333545131 is an equidigital number, since it uses as much as digits as its factorization.
21333545131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16200, while the sum is 31.
The spelling of 21333545131 in words is "twenty-one billion, three hundred thirty-three million, five hundred forty-five thousand, one hundred thirty-one".
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