Base | Representation |
---|---|
bin | 1001101100111100011001… |
… | …00001010110100001010111 |
3 | 2210112122112220021022110211 |
4 | 10312132030201112201113 |
5 | 10244030010242044341 |
6 | 113213213003030251 |
7 | 4331302406464351 |
oct | 466361441264127 |
9 | 83478486238424 |
10 | 21335460112471 |
11 | 68863550235aa |
12 | 2486b5650b387 |
13 | bb9c04a2c63b |
14 | 53a8db0840d1 |
15 | 26eeb6e26181 |
hex | 13678c856857 |
21335460112471 has 2 divisors, whose sum is σ = 21335460112472. Its totient is φ = 21335460112470.
The previous prime is 21335460112391. The next prime is 21335460112501. The reversal of 21335460112471 is 17421106453312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21335460112471 - 213 = 21335460104279 is a prime.
It is a super-3 number, since 3×213354601124713 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21335460112171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10667730056235 + 10667730056236.
It is an arithmetic number, because the mean of its divisors is an integer number (10667730056236).
Almost surely, 221335460112471 is an apocalyptic number.
21335460112471 is a deficient number, since it is larger than the sum of its proper divisors (1).
21335460112471 is an equidigital number, since it uses as much as digits as its factorization.
21335460112471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 40.
Adding to 21335460112471 its reverse (17421106453312), we get a palindrome (38756566565783).
The spelling of 21335460112471 in words is "twenty-one trillion, three hundred thirty-five billion, four hundred sixty million, one hundred twelve thousand, four hundred seventy-one".
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