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213400673531 is a prime number
BaseRepresentation
bin1100011010111110101…
…0111101110011111011
3202101211021000102201022
43012233222331303323
511444021033023111
6242011313013055
721263160540023
oct3065752756373
9671737012638
10213400673531
1182559131601
123543755418b
131717b709bb6
14a485b48a83
15583eb6e2db
hex31afabdcfb

213400673531 has 2 divisors, whose sum is σ = 213400673532. Its totient is φ = 213400673530.

The previous prime is 213400673513. The next prime is 213400673533. The reversal of 213400673531 is 135376004312.

Together with previous prime (213400673513) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 213400673531 - 214 = 213400657147 is a prime.

It is a super-2 number, since 2×2134006735312 (a number of 23 digits) contains 22 as substring.

Together with 213400673533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 213400673491 and 213400673500.

It is not a weakly prime, because it can be changed into another prime (213400673533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106700336765 + 106700336766.

It is an arithmetic number, because the mean of its divisors is an integer number (106700336766).

Almost surely, 2213400673531 is an apocalyptic number.

213400673531 is a deficient number, since it is larger than the sum of its proper divisors (1).

213400673531 is an equidigital number, since it uses as much as digits as its factorization.

213400673531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45360, while the sum is 35.

Adding to 213400673531 its reverse (135376004312), we get a palindrome (348776677843).

The spelling of 213400673531 in words is "two hundred thirteen billion, four hundred million, six hundred seventy-three thousand, five hundred thirty-one".