Base | Representation |
---|---|
bin | 110000100001011011111110… |
… | …110100010111111001100100 |
3 | 1000222121020002002102211222112 |
4 | 300201123332310113321210 |
5 | 210432402413133230200 |
6 | 2033512241541220152 |
7 | 62643634363242662 |
oct | 6041337664277144 |
9 | 1028536062384875 |
10 | 213404020211300 |
11 | 61aa7155a83716 |
12 | 1bb27166701658 |
13 | 920cbb3432689 |
14 | 3a9ab49b03c32 |
15 | 19a11dd038535 |
hex | c216fed17e64 |
213404020211300 has 72 divisors (see below), whose sum is σ = 464488208768640. Its totient is φ = 85103409801600.
The previous prime is 213404020211159. The next prime is 213404020211309. The reversal of 213404020211300 is 3112020404312.
It is not an unprimeable number, because it can be changed into a prime (213404020211309) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 121374866 + ... + 123120534.
Almost surely, 2213404020211300 is an apocalyptic number.
213404020211300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
213404020211300 is an abundant number, since it is smaller than the sum of its proper divisors (251084188557340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213404020211300 is a wasteful number, since it uses less digits than its factorization.
213404020211300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1749381 (or 1749374 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 213404020211300 its reverse (3112020404312), we get a palindrome (216516040615612).
The spelling of 213404020211300 in words is "two hundred thirteen trillion, four hundred four billion, twenty million, two hundred eleven thousand, three hundred".
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