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213413533477 is a prime number
BaseRepresentation
bin1100011011000001110…
…0000001011100100101
3202101212011012210020121
43012300130001130211
511444032331032402
6242012452401541
721263405050414
oct3066034013445
9671764183217
10213413533477
1182565415461
123543b9162b1
1317181290431
14a48773547b
155840d5e837
hex31b0701725

213413533477 has 2 divisors, whose sum is σ = 213413533478. Its totient is φ = 213413533476.

The previous prime is 213413533451. The next prime is 213413533481. The reversal of 213413533477 is 774335314312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 169520769441 + 43892764036 = 411729^2 + 209506^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213413533477 is a prime.

It is a super-2 number, since 2×2134135334772 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213413533577) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106706766738 + 106706766739.

It is an arithmetic number, because the mean of its divisors is an integer number (106706766739).

Almost surely, 2213413533477 is an apocalyptic number.

It is an amenable number.

213413533477 is a deficient number, since it is larger than the sum of its proper divisors (1).

213413533477 is an equidigital number, since it uses as much as digits as its factorization.

213413533477 is an evil number, because the sum of its binary digits is even.

The product of its digits is 635040, while the sum is 43.

Adding to 213413533477 its reverse (774335314312), we get a palindrome (987748847789).

It can be divided in two parts, 2134135 and 33477, that added together give a palindrome (2167612).

The spelling of 213413533477 in words is "two hundred thirteen billion, four hundred thirteen million, five hundred thirty-three thousand, four hundred seventy-seven".