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213414125001617 is a prime number
BaseRepresentation
bin110000100001100101011001…
…000111000101101110010001
31000222122012011022101101101202
4300201211121013011232101
5210433034112000022432
62033521032350040545
762644442652451031
oct6041453107055621
91028565138341352
10213414125001617
11620004709611a1
121bb291067a9155
139210b33a4cb47
143a9b427b438c1
1519a15d01e5462
hexc219591c5b91

213414125001617 has 2 divisors, whose sum is σ = 213414125001618. Its totient is φ = 213414125001616.

The previous prime is 213414125001577. The next prime is 213414125001643. The reversal of 213414125001617 is 716100521414312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 198576459824656 + 14837665176961 = 14091716^2 + 3851969^2 .

It is a cyclic number.

It is not a de Polignac number, because 213414125001617 - 234 = 213396945132433 is a prime.

It is a super-2 number, since 2×2134141250016172 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (213414125001017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106707062500808 + 106707062500809.

It is an arithmetic number, because the mean of its divisors is an integer number (106707062500809).

Almost surely, 2213414125001617 is an apocalyptic number.

It is an amenable number.

213414125001617 is a deficient number, since it is larger than the sum of its proper divisors (1).

213414125001617 is an equidigital number, since it uses as much as digits as its factorization.

213414125001617 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40320, while the sum is 38.

Adding to 213414125001617 its reverse (716100521414312), we get a palindrome (929514646415929).

The spelling of 213414125001617 in words is "two hundred thirteen trillion, four hundred fourteen billion, one hundred twenty-five million, one thousand, six hundred seventeen".