Base | Representation |
---|---|
bin | 1001101101001000100100… |
… | …11101100110001010010111 |
3 | 2210120021102211102221022212 |
4 | 10312210102131212022113 |
5 | 10244131410033222244 |
6 | 113220214103344035 |
7 | 4331623465615022 |
oct | 466442235461227 |
9 | 83507384387285 |
10 | 21342002242199 |
11 | 6889101976491 |
12 | 248828145201b |
13 | bba708211512 |
14 | 53ad5bc941b9 |
15 | 27024b449d9e |
hex | 136912766297 |
21342002242199 has 2 divisors, whose sum is σ = 21342002242200. Its totient is φ = 21342002242198.
The previous prime is 21342002242189. The next prime is 21342002242291. The reversal of 21342002242199 is 99124220024312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21342002242199 - 28 = 21342002241943 is a prime.
It is a super-3 number, since 3×213420022421993 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21342002242109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10671001121099 + 10671001121100.
It is an arithmetic number, because the mean of its divisors is an integer number (10671001121100).
Almost surely, 221342002242199 is an apocalyptic number.
21342002242199 is a deficient number, since it is larger than the sum of its proper divisors (1).
21342002242199 is an equidigital number, since it uses as much as digits as its factorization.
21342002242199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 41.
The spelling of 21342002242199 in words is "twenty-one trillion, three hundred forty-two billion, two million, two hundred forty-two thousand, one hundred ninety-nine".
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