Base | Representation |
---|---|
bin | 1100011011000011010… |
… | …1001001110101001100 |
3 | 202101212121121111012111 |
4 | 3012300311021311030 |
5 | 11444041022341140 |
6 | 242013245513404 |
7 | 21263515046302 |
oct | 3066065116514 |
9 | 671777544174 |
10 | 213420121420 |
11 | 82569105040 |
12 | 35441b72864 |
13 | 17182758c1c |
14 | a48856c272 |
15 | 58417117ea |
hex | 31b0d49d4c |
213420121420 has 24 divisors (see below), whose sum is σ = 488926096848. Its totient is φ = 77607316800.
The previous prime is 213420121417. The next prime is 213420121451. The reversal of 213420121420 is 24121024312.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a junction number, because it is equal to n+sod(n) for n = 213420121391 and 213420121400.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 485045511 + ... + 485045950.
It is an arithmetic number, because the mean of its divisors is an integer number (20371920702).
Almost surely, 2213420121420 is an apocalyptic number.
213420121420 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
213420121420 is an abundant number, since it is smaller than the sum of its proper divisors (275505975428).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213420121420 is a wasteful number, since it uses less digits than its factorization.
213420121420 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 970091481 (or 970091479 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 213420121420 its reverse (24121024312), we get a palindrome (237541145732).
The spelling of 213420121420 in words is "two hundred thirteen billion, four hundred twenty million, one hundred twenty-one thousand, four hundred twenty".
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