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2134365137 is a prime number
BaseRepresentation
bin111111100110111…
…1101001111010001
312111202011222112122
41333031331033101
513332344141022
6551442504025
7103614542612
oct17715751721
95452158478
102134365137
119a5880133
124b6965015
13280260968
14163673c09
15c75a4742
hex7f37d3d1

2134365137 has 2 divisors, whose sum is σ = 2134365138. Its totient is φ = 2134365136.

The previous prime is 2134365049. The next prime is 2134365139. The reversal of 2134365137 is 7315634312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1997732416 + 136632721 = 44696^2 + 11689^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2134365137 is a prime.

Together with 2134365139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2134365097 and 2134365106.

It is not a weakly prime, because it can be changed into another prime (2134365139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067182568 + 1067182569.

It is an arithmetic number, because the mean of its divisors is an integer number (1067182569).

Almost surely, 22134365137 is an apocalyptic number.

It is an amenable number.

2134365137 is a deficient number, since it is larger than the sum of its proper divisors (1).

2134365137 is an equidigital number, since it uses as much as digits as its factorization.

2134365137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 45360, while the sum is 35.

The square root of 2134365137 is about 46199.1897872679. The cubic root of 2134365137 is about 1287.5266867501.

Adding to 2134365137 its reverse (7315634312), we get a palindrome (9449999449).

The spelling of 2134365137 in words is "two billion, one hundred thirty-four million, three hundred sixty-five thousand, one hundred thirty-seven".