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213441001453 is a prime number
BaseRepresentation
bin1100011011001000010…
…0110011011111101101
3202101221001220022020001
43012302010303133231
511444111344021303
6242015313224301
721264160402111
oct3066204633755
9671831808201
10213441001453
1182579976569
1235448b62091
1317186b89a84
14a48b245741
15584348831d
hex31b21337ed

213441001453 has 2 divisors, whose sum is σ = 213441001454. Its totient is φ = 213441001452.

The previous prime is 213441001387. The next prime is 213441001517. The reversal of 213441001453 is 354100144312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107375493124 + 106065508329 = 327682^2 + 325677^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213441001453 is a prime.

It is a super-2 number, since 2×2134410014532 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213441001853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106720500726 + 106720500727.

It is an arithmetic number, because the mean of its divisors is an integer number (106720500727).

Almost surely, 2213441001453 is an apocalyptic number.

It is an amenable number.

213441001453 is a deficient number, since it is larger than the sum of its proper divisors (1).

213441001453 is an equidigital number, since it uses as much as digits as its factorization.

213441001453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 213441001453 its reverse (354100144312), we get a palindrome (567541145765).

The spelling of 213441001453 in words is "two hundred thirteen billion, four hundred forty-one million, one thousand, four hundred fifty-three".