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21345313115461 is a prime number
BaseRepresentation
bin1001101101001110101111…
…10011100100110101000101
32210120120222120102201121111
410312213113303210311011
510244210200124143321
6113221522415045021
74332101520564526
oct466472763446505
983516876381544
1021345313115461
11688a550867585
122488a46210771
13bbab1512ca1a
1453b1938a084d
15270391e495e1
hex1369d7ce4d45

21345313115461 has 2 divisors, whose sum is σ = 21345313115462. Its totient is φ = 21345313115460.

The previous prime is 21345313115377. The next prime is 21345313115509. The reversal of 21345313115461 is 16451131354312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16419465784836 + 4925847330625 = 4052094^2 + 2219425^2 .

It is a cyclic number.

It is not a de Polignac number, because 21345313115461 - 217 = 21345312984389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21345313110461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10672656557730 + 10672656557731.

It is an arithmetic number, because the mean of its divisors is an integer number (10672656557731).

Almost surely, 221345313115461 is an apocalyptic number.

It is an amenable number.

21345313115461 is a deficient number, since it is larger than the sum of its proper divisors (1).

21345313115461 is an equidigital number, since it uses as much as digits as its factorization.

21345313115461 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 129600, while the sum is 40.

Adding to 21345313115461 its reverse (16451131354312), we get a palindrome (37796444469773).

The spelling of 21345313115461 in words is "twenty-one trillion, three hundred forty-five billion, three hundred thirteen million, one hundred fifteen thousand, four hundred sixty-one".