Base | Representation |
---|---|
bin | 11111000100010111111… |
… | …111001111101010111101 |
3 | 21120002210220102110002012 |
4 | 133010113333033222331 |
5 | 234434440301420331 |
6 | 4312450033141005 |
7 | 310151214532241 |
oct | 37042777175275 |
9 | 7502726373065 |
10 | 2135001201341 |
11 | 7534a3578568 |
12 | 2a593b6ba765 |
13 | 1264395c8528 |
14 | 75498250421 |
15 | 3a809e3382b |
hex | 1f117fcfabd |
2135001201341 has 2 divisors, whose sum is σ = 2135001201342. Its totient is φ = 2135001201340.
The previous prime is 2135001201331. The next prime is 2135001201449. The reversal of 2135001201341 is 1431021005312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1912816238116 + 222184963225 = 1383046^2 + 471365^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2135001201341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2135001201331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067500600670 + 1067500600671.
It is an arithmetic number, because the mean of its divisors is an integer number (1067500600671).
Almost surely, 22135001201341 is an apocalyptic number.
It is an amenable number.
2135001201341 is a deficient number, since it is larger than the sum of its proper divisors (1).
2135001201341 is an equidigital number, since it uses as much as digits as its factorization.
2135001201341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 2135001201341 its reverse (1431021005312), we get a palindrome (3566022206653).
The spelling of 2135001201341 in words is "two trillion, one hundred thirty-five billion, one million, two hundred one thousand, three hundred forty-one".
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