Base | Representation |
---|---|
bin | 1001101101011011011011… |
… | …10010111111010100001111 |
3 | 2210121020120021021111101222 |
4 | 10312231231302333110033 |
5 | 10244313122333332003 |
6 | 113225010334553555 |
7 | 4332432356522162 |
oct | 466555562772417 |
9 | 83536507244358 |
10 | 21352124511503 |
11 | 6892426702205 |
12 | 248a2273688bb |
13 | bbb65c33b796 |
14 | 53b63c363ad9 |
15 | 27063ee0ac38 |
hex | 136b6dcbf50f |
21352124511503 has 2 divisors, whose sum is σ = 21352124511504. Its totient is φ = 21352124511502.
The previous prime is 21352124511427. The next prime is 21352124511517. The reversal of 21352124511503 is 30511542125312.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21352124511503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21352124511203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10676062255751 + 10676062255752.
It is an arithmetic number, because the mean of its divisors is an integer number (10676062255752).
Almost surely, 221352124511503 is an apocalyptic number.
21352124511503 is a deficient number, since it is larger than the sum of its proper divisors (1).
21352124511503 is an equidigital number, since it uses as much as digits as its factorization.
21352124511503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 21352124511503 its reverse (30511542125312), we get a palindrome (51863666636815).
The spelling of 21352124511503 in words is "twenty-one trillion, three hundred fifty-two billion, one hundred twenty-four million, five hundred eleven thousand, five hundred three".
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