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21362122126337 is a prime number
BaseRepresentation
bin1001101101101110000011…
…01100110111010000000001
32210122012101000112221200212
410312313001230313100001
510244444111231020322
6113233342354323505
74333235205041246
oct466670154672001
983565330487625
1021362122126337
116896697038203
122490157589595
13bbc5936a23c5
1453bd0a0655cd
15270a279970e2
hex136dc1b37401

21362122126337 has 2 divisors, whose sum is σ = 21362122126338. Its totient is φ = 21362122126336.

The previous prime is 21362122126307. The next prime is 21362122126339. The reversal of 21362122126337 is 73362122126312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20666697892096 + 695424234241 = 4546064^2 + 833921^2 .

It is a cyclic number.

It is not a de Polignac number, because 21362122126337 - 230 = 21361048384513 is a prime.

Together with 21362122126339, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 21362122126294 and 21362122126303.

It is not a weakly prime, because it can be changed into another prime (21362122126339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10681061063168 + 10681061063169.

It is an arithmetic number, because the mean of its divisors is an integer number (10681061063169).

Almost surely, 221362122126337 is an apocalyptic number.

It is an amenable number.

21362122126337 is a deficient number, since it is larger than the sum of its proper divisors (1).

21362122126337 is an equidigital number, since it uses as much as digits as its factorization.

21362122126337 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 217728, while the sum is 41.

The spelling of 21362122126337 in words is "twenty-one trillion, three hundred sixty-two billion, one hundred twenty-two million, one hundred twenty-six thousand, three hundred thirty-seven".