Base | Representation |
---|---|
bin | 1100011100100110101… |
… | …0110101011100001111 |
3 | 202102221122202100001011 |
4 | 3013021222311130033 |
5 | 12000414213044423 |
6 | 242122453430051 |
7 | 21310035131263 |
oct | 3071152653417 |
9 | 672848670034 |
10 | 213836846863 |
11 | 82762364032 |
12 | 3553963b327 |
13 | 1721aba5323 |
14 | a4c7a480a3 |
15 | 58680cab0d |
hex | 31c9ab570f |
213836846863 has 2 divisors, whose sum is σ = 213836846864. Its totient is φ = 213836846862.
The previous prime is 213836846801. The next prime is 213836846869. The reversal of 213836846863 is 368648638312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213836846863 - 29 = 213836846351 is a prime.
It is a super-3 number, since 3×2138368468633 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 213836846798 and 213836846807.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213836846869) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106918423431 + 106918423432.
It is an arithmetic number, because the mean of its divisors is an integer number (106918423432).
Almost surely, 2213836846863 is an apocalyptic number.
213836846863 is a deficient number, since it is larger than the sum of its proper divisors (1).
213836846863 is an equidigital number, since it uses as much as digits as its factorization.
213836846863 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 23887872, while the sum is 58.
The spelling of 213836846863 in words is "two hundred thirteen billion, eight hundred thirty-six million, eight hundred forty-six thousand, eight hundred sixty-three".
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