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2138406724813 is a prime number
BaseRepresentation
bin11111000111100010111…
…110010010010011001101
321120102121020111222001011
4133013202332102103031
5240013424110143223
64314212005245221
7310331466153142
oct37074276222315
97512536458034
102138406724813
11754990936777
122a6530103811
13126860006488
14756dc6583c9
153a958dcc80d
hex1f1e2f924cd

2138406724813 has 2 divisors, whose sum is σ = 2138406724814. Its totient is φ = 2138406724812.

The previous prime is 2138406724799. The next prime is 2138406724819. The reversal of 2138406724813 is 3184276048312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1715057398404 + 423349326409 = 1309602^2 + 650653^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2138406724813 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2138406724819) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1069203362406 + 1069203362407.

It is an arithmetic number, because the mean of its divisors is an integer number (1069203362407).

Almost surely, 22138406724813 is an apocalyptic number.

It is an amenable number.

2138406724813 is a deficient number, since it is larger than the sum of its proper divisors (1).

2138406724813 is an equidigital number, since it uses as much as digits as its factorization.

2138406724813 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1548288, while the sum is 49.

The spelling of 2138406724813 in words is "two trillion, one hundred thirty-eight billion, four hundred six million, seven hundred twenty-four thousand, eight hundred thirteen".