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213843002880041 is a prime number
BaseRepresentation
bin110000100111110100110100…
…001110010111000000101001
31001001011012011112202222100022
4300213310310032113000221
5211012100432214130131
62034450041435250225
763020434650331313
oct6047646416270051
91031135145688308
10213843002880041
1162156343283017
121bb98258ba9975
1392424021285c2
143ab40b12d47b3
1519ac831e6237b
hexc27d34397029

213843002880041 has 2 divisors, whose sum is σ = 213843002880042. Its totient is φ = 213843002880040.

The previous prime is 213843002879971. The next prime is 213843002880043. The reversal of 213843002880041 is 140088200348312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108836972790016 + 105006030090025 = 10432496^2 + 10247245^2 .

It is a cyclic number.

It is not a de Polignac number, because 213843002880041 - 218 = 213843002617897 is a prime.

Together with 213843002880043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 213843002879974 and 213843002880001.

It is not a weakly prime, because it can be changed into another prime (213843002880043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106921501440020 + 106921501440021.

It is an arithmetic number, because the mean of its divisors is an integer number (106921501440021).

Almost surely, 2213843002880041 is an apocalyptic number.

It is an amenable number.

213843002880041 is a deficient number, since it is larger than the sum of its proper divisors (1).

213843002880041 is an equidigital number, since it uses as much as digits as its factorization.

213843002880041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 294912, while the sum is 44.

The spelling of 213843002880041 in words is "two hundred thirteen trillion, eight hundred forty-three billion, two million, eight hundred eighty thousand, forty-one".