Base | Representation |
---|---|
bin | 1100011100110011001… |
… | …0100100001100111011 |
3 | 202110002022021101222022 |
4 | 3013030302210030323 |
5 | 12001021114030201 |
6 | 242132003545055 |
7 | 21311242150124 |
oct | 3071462441473 |
9 | 673068241868 |
10 | 213889205051 |
11 | 82789975565 |
12 | 3555308b18b |
13 | 172289a7bc2 |
14 | a4d099704b |
15 | 586c9be41b |
hex | 31ccca433b |
213889205051 has 2 divisors, whose sum is σ = 213889205052. Its totient is φ = 213889205050.
The previous prime is 213889205029. The next prime is 213889205053. The reversal of 213889205051 is 150502988312.
213889205051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213889205051 - 218 = 213888942907 is a prime.
Together with 213889205053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 213889204993 and 213889205011.
It is not a weakly prime, because it can be changed into another prime (213889205053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106944602525 + 106944602526.
It is an arithmetic number, because the mean of its divisors is an integer number (106944602526).
Almost surely, 2213889205051 is an apocalyptic number.
213889205051 is a deficient number, since it is larger than the sum of its proper divisors (1).
213889205051 is an equidigital number, since it uses as much as digits as its factorization.
213889205051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 44.
The spelling of 213889205051 in words is "two hundred thirteen billion, eight hundred eighty-nine million, two hundred five thousand, fifty-one".
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