Base | Representation |
---|---|
bin | 1001101110110100110110… |
… | …01110000100001000111011 |
3 | 2210202211110221101011210022 |
4 | 10313122123032010020323 |
5 | 10301104432043132443 |
6 | 113303030133241055 |
7 | 4336052126041361 |
oct | 467323316041073 |
9 | 83684427334708 |
10 | 21400131224123 |
11 | 69008211a2a13 |
12 | 24975a479318b |
13 | bc3040144602 |
14 | 53dab4065631 |
15 | 2719ee7b6e68 |
hex | 13769b38423b |
21400131224123 has 2 divisors, whose sum is σ = 21400131224124. Its totient is φ = 21400131224122.
The previous prime is 21400131224113. The next prime is 21400131224183. The reversal of 21400131224123 is 32142213100412.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21400131224123 - 24 = 21400131224107 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21400131224092 and 21400131224101.
It is not a weakly prime, because it can be changed into another prime (21400131224113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10700065612061 + 10700065612062.
It is an arithmetic number, because the mean of its divisors is an integer number (10700065612062).
Almost surely, 221400131224123 is an apocalyptic number.
21400131224123 is a deficient number, since it is larger than the sum of its proper divisors (1).
21400131224123 is an equidigital number, since it uses as much as digits as its factorization.
21400131224123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 21400131224123 its reverse (32142213100412), we get a palindrome (53542344324535).
The spelling of 21400131224123 in words is "twenty-one trillion, four hundred billion, one hundred thirty-one million, two hundred twenty-four thousand, one hundred twenty-three".
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