Base | Representation |
---|---|
bin | 1100011101001110100… |
… | …1001111001011110101 |
3 | 202110101022122202122012 |
4 | 3013103221033023311 |
5 | 12001240033401211 |
6 | 242151232414005 |
7 | 21314136454652 |
oct | 3072351171365 |
9 | 673338582565 |
10 | 214004200181 |
11 | 82838879062 |
12 | 355856a7305 |
13 | 1724676ba65 |
14 | a501d6cc29 |
15 | 5877b36d8b |
hex | 31d3a4f2f5 |
214004200181 has 2 divisors, whose sum is σ = 214004200182. Its totient is φ = 214004200180.
The previous prime is 214004200079. The next prime is 214004200187. The reversal of 214004200181 is 181002400412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 210327718225 + 3676481956 = 458615^2 + 60634^2 .
It is a cyclic number.
It is not a de Polignac number, because 214004200181 - 214 = 214004183797 is a prime.
It is a super-2 number, since 2×2140042001812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214004200187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107002100090 + 107002100091.
It is an arithmetic number, because the mean of its divisors is an integer number (107002100091).
Almost surely, 2214004200181 is an apocalyptic number.
It is an amenable number.
214004200181 is a deficient number, since it is larger than the sum of its proper divisors (1).
214004200181 is an equidigital number, since it uses as much as digits as its factorization.
214004200181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 512, while the sum is 23.
Adding to 214004200181 its reverse (181002400412), we get a palindrome (395006600593).
The spelling of 214004200181 in words is "two hundred fourteen billion, four million, two hundred thousand, one hundred eighty-one".
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