21401211444125 has 16 divisors (see below), whose sum is σ = 26745450251520. Its totient is φ = 17097418918800.

The previous prime is 21401211444031. The next prime is 21401211444157. The reversal of 21401211444125 is 52144411210412.

It is not a de Polignac number, because 21401211444125 - 2²⁰ = 21401210395549 is a prime.

It is a super-2 number, since 2×21401211444125² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21401211444091 and 21401211444100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 117659945 + ... + 117841694.

It is an arithmetic number, because the mean of its divisors is an integer number (1671590640720).

Almost surely, 2^{21401211444125} is an apocalyptic number.

21401211444125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

It is an amenable number.

21401211444125 is a deficient number, since it is larger than the sum of its proper divisors (5344238807395).

21401211444125 is an equidigital number, since it uses as much as digits as its factorization.

21401211444125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 235502381 (or 235502371 counting only the distinct ones).

The product of its (nonzero) digits is 10240, while the sum is 32.

Adding to 21401211444125 its reverse (52144411210412), we get a palindrome (73545622654537).

The spelling of 21401211444125 in words is "twenty-one trillion, four hundred one billion, two hundred eleven million, four hundred forty-four thousand, one hundred twenty-five".