Base | Representation |
---|---|
bin | 1001101110110110110111… |
… | …01011010000111010001011 |
3 | 2210202221021022012210122021 |
4 | 10313123123223100322023 |
5 | 10301114140412323202 |
6 | 113303325323305311 |
7 | 4336120666542313 |
oct | 467333353207213 |
9 | 83687238183567 |
10 | 21401212620427 |
11 | 6901226660a72 |
12 | 249784697b237 |
13 | bc31831b0593 |
14 | 53db77920443 |
15 | 271a646c5a37 |
hex | 1376dbad0e8b |
21401212620427 has 2 divisors, whose sum is σ = 21401212620428. Its totient is φ = 21401212620426.
The previous prime is 21401212620377. The next prime is 21401212620479. The reversal of 21401212620427 is 72402621210412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21401212620427 - 215 = 21401212587659 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21401212620392 and 21401212620401.
It is not a weakly prime, because it can be changed into another prime (21401212660427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10700606310213 + 10700606310214.
It is an arithmetic number, because the mean of its divisors is an integer number (10700606310214).
Almost surely, 221401212620427 is an apocalyptic number.
21401212620427 is a deficient number, since it is larger than the sum of its proper divisors (1).
21401212620427 is an equidigital number, since it uses as much as digits as its factorization.
21401212620427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 34.
Adding to 21401212620427 its reverse (72402621210412), we get a palindrome (93803833830839).
The spelling of 21401212620427 in words is "twenty-one trillion, four hundred one billion, two hundred twelve million, six hundred twenty thousand, four hundred twenty-seven".
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