Base | Representation |
---|---|
bin | 1100011101010000100… |
… | …0001000111101000101 |
3 | 202110101212220100001011 |
4 | 3013110020020331011 |
5 | 12001244122114000 |
6 | 242152122202221 |
7 | 21314265354610 |
oct | 3072410107505 |
9 | 673355810034 |
10 | 214012301125 |
11 | 82842401457 |
12 | 35588353371 |
13 | 1724834710c |
14 | a50307b177 |
15 | 58786d72ba |
hex | 31d4208f45 |
214012301125 has 16 divisors (see below), whose sum is σ = 305242689024. Its totient is φ = 146751291600.
The previous prime is 214012301077. The next prime is 214012301179. The reversal of 214012301125 is 521103210412.
It is not a de Polignac number, because 214012301125 - 225 = 213978746693 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 214012301096 and 214012301105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 122291869 + ... + 122293618.
It is an arithmetic number, because the mean of its divisors is an integer number (19077668064).
Almost surely, 2214012301125 is an apocalyptic number.
214012301125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
214012301125 is a deficient number, since it is larger than the sum of its proper divisors (91230387899).
214012301125 is an equidigital number, since it uses as much as digits as its factorization.
214012301125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 244585509 (or 244585499 counting only the distinct ones).
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 214012301125 its reverse (521103210412), we get a palindrome (735115511537).
The spelling of 214012301125 in words is "two hundred fourteen billion, twelve million, three hundred one thousand, one hundred twenty-five".
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