Base | Representation |
---|---|
bin | 110000101010010011001011… |
… | …011111011100101111101110 |
3 | 1001001202110002000222102200202 |
4 | 300222103023133130233232 |
5 | 211022342203334203032 |
6 | 2035100122500153502 |
7 | 63035634514640516 |
oct | 6052231337345756 |
9 | 1031673060872622 |
10 | 214013044444142 |
11 | 62211471309989 |
12 | 200051b3698892 |
13 | 9255460876118 |
14 | 3abc4026aa846 |
15 | 19b1e8526cd62 |
hex | c2a4cb7dcbee |
214013044444142 has 8 divisors (see below), whose sum is σ = 321019713815736. Its totient is φ = 107006473172232.
The previous prime is 214013044444141. The next prime is 214013044444211. The reversal of 214013044444142 is 241444440310412.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 214013044444096 and 214013044444105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (214013044444141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18804053 + ... + 27957440.
It is an arithmetic number, because the mean of its divisors is an integer number (40127464226967).
Almost surely, 2214013044444142 is an apocalyptic number.
214013044444142 is a deficient number, since it is larger than the sum of its proper divisors (107006669371594).
214013044444142 is a wasteful number, since it uses less digits than its factorization.
214013044444142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49049842.
The product of its (nonzero) digits is 196608, while the sum is 38.
Adding to 214013044444142 its reverse (241444440310412), we get a palindrome (455457484754554).
The spelling of 214013044444142 in words is "two hundred fourteen trillion, thirteen billion, forty-four million, four hundred forty-four thousand, one hundred forty-two".
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