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2140131001 is a prime number
BaseRepresentation
bin111111110001111…
…1100111010111001
312112011000220211011
41333203330322321
513340333143001
6552210233521
7104014545661
oct17743747271
95464026734
102140131001
119a9059108
124b88858a1
132814cc208
141643351a1
15c7d42d51
hex7f8fceb9

2140131001 has 2 divisors, whose sum is σ = 2140131002. Its totient is φ = 2140131000.

The previous prime is 2140130989. The next prime is 2140131031. The reversal of 2140131001 is 1001310412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1566576400 + 573554601 = 39580^2 + 23949^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2140131001 is a prime.

It is not a weakly prime, because it can be changed into another prime (2140131031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070065500 + 1070065501.

It is an arithmetic number, because the mean of its divisors is an integer number (1070065501).

Almost surely, 22140131001 is an apocalyptic number.

It is an amenable number.

2140131001 is a deficient number, since it is larger than the sum of its proper divisors (1).

2140131001 is an equidigital number, since it uses as much as digits as its factorization.

2140131001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 2140131001 is about 46261.5499199930. The cubic root of 2140131001 is about 1288.6850372679.

Adding to 2140131001 its reverse (1001310412), we get a palindrome (3141441413).

The spelling of 2140131001 in words is "two billion, one hundred forty million, one hundred thirty-one thousand, one".