Base | Representation |
---|---|
bin | 11111001001001100001… |
… | …000011110000010101001 |
3 | 21120121011012022112101121 |
4 | 133021030020132002221 |
5 | 240031032234031100 |
6 | 4315103032015241 |
7 | 310423301235400 |
oct | 37111410360251 |
9 | 7517135275347 |
10 | 2140171002025 |
11 | 755706811311 |
12 | 2a6942b31521 |
13 | 126a816997a4 |
14 | 75828ab2637 |
15 | 3aa0dc2b51a |
hex | 1f24c21e0a9 |
2140171002025 has 72 divisors (see below), whose sum is σ = 3139442527104. Its totient is φ = 1442684073600.
The previous prime is 2140171002019. The next prime is 2140171002037. The reversal of 2140171002025 is 5202001710412.
It is not a de Polignac number, because 2140171002025 - 217 = 2140170870953 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 154150734 + ... + 154164616.
It is an arithmetic number, because the mean of its divisors is an integer number (43603368432).
Almost surely, 22140171002025 is an apocalyptic number.
2140171002025 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
2140171002025 is a deficient number, since it is larger than the sum of its proper divisors (999271525079).
2140171002025 is a wasteful number, since it uses less digits than its factorization.
2140171002025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16031 (or 16019 counting only the distinct ones).
The product of its (nonzero) digits is 1120, while the sum is 25.
Adding to 2140171002025 its reverse (5202001710412), we get a palindrome (7342172712437).
The spelling of 2140171002025 in words is "two trillion, one hundred forty billion, one hundred seventy-one million, two thousand, twenty-five".
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