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2140220131141 is a prime number
BaseRepresentation
bin11111001001001111000…
…011111000011101000101
321120121021121202112212111
4133021033003320131011
5240031132323144031
64315111545021021
7310424435645101
oct37111703703505
97517247675774
102140220131141
11755731517794
122a6957484771
13126a8b90b681
1475831420901
153aa131d31b1
hex1f24f0f8745

2140220131141 has 2 divisors, whose sum is σ = 2140220131142. Its totient is φ = 2140220131140.

The previous prime is 2140220131109. The next prime is 2140220131157. The reversal of 2140220131141 is 1411310220412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1444614090241 + 695606040900 = 1201921^2 + 834030^2 .

It is a cyclic number.

It is not a de Polignac number, because 2140220131141 - 25 = 2140220131109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2140220131171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070110065570 + 1070110065571.

It is an arithmetic number, because the mean of its divisors is an integer number (1070110065571).

Almost surely, 22140220131141 is an apocalyptic number.

It is an amenable number.

2140220131141 is a deficient number, since it is larger than the sum of its proper divisors (1).

2140220131141 is an equidigital number, since it uses as much as digits as its factorization.

2140220131141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 2140220131141 its reverse (1411310220412), we get a palindrome (3551530351553).

The spelling of 2140220131141 in words is "two trillion, one hundred forty billion, two hundred twenty million, one hundred thirty-one thousand, one hundred forty-one".