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2140251345013 = 7306129294033
BaseRepresentation
bin11111001001010000111…
…010111101000001110101
321120121100210111101020211
4133021100322331001311
5240031213321020023
64315115022025421
7310425265160455
oct37112072750165
97517323441224
102140251345013
117557480a7181
122a6965a18271
13126a9521a012
1475835627d65
153aa15ceba0d
hex1f250ebd075

2140251345013 has 4 divisors (see below), whose sum is σ = 2140280712108. Its totient is φ = 2140221977920.

The previous prime is 2140251344971. The next prime is 2140251345019. The reversal of 2140251345013 is 3105431520412.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 187474278289 + 1952777066724 = 432983^2 + 1397418^2 .

It is a cyclic number.

It is not a de Polignac number, because 2140251345013 - 229 = 2139714474101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2140251345019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14573956 + ... + 14720077.

It is an arithmetic number, because the mean of its divisors is an integer number (535070178027).

Almost surely, 22140251345013 is an apocalyptic number.

It is an amenable number.

2140251345013 is a deficient number, since it is larger than the sum of its proper divisors (29367095).

2140251345013 is an equidigital number, since it uses as much as digits as its factorization.

2140251345013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29367094.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 2140251345013 its reverse (3105431520412), we get a palindrome (5245682865425).

The spelling of 2140251345013 in words is "two trillion, one hundred forty billion, two hundred fifty-one million, three hundred forty-five thousand, thirteen".

Divisors: 1 73061 29294033 2140251345013