Base | Representation |
---|---|
bin | 11111001001010000111… |
… | …010111101000001110100 |
3 | 21120121100210111101020210 |
4 | 133021100322331001310 |
5 | 240031213321020022 |
6 | 4315115022025420 |
7 | 310425265160454 |
oct | 37112072750164 |
9 | 7517323441223 |
10 | 2140251345012 |
11 | 7557480a7180 |
12 | 2a6965a18270 |
13 | 126a9521a011 |
14 | 75835627d64 |
15 | 3aa15ceba0c |
hex | 1f250ebd074 |
2140251345012 has 48 divisors (see below), whose sum is σ = 5448980984832. Its totient is φ = 648433814880.
The previous prime is 2140251344971. The next prime is 2140251345019. The reversal of 2140251345012 is 2105431520412.
It is a super-3 number, since 3×21402513450123 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2140251345019) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 913308 + ... + 2261555.
It is an arithmetic number, because the mean of its divisors is an integer number (113520437184).
Almost surely, 22140251345012 is an apocalyptic number.
2140251345012 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is an amenable number.
2140251345012 is an abundant number, since it is smaller than the sum of its proper divisors (3308729639820).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2140251345012 is a wasteful number, since it uses less digits than its factorization.
2140251345012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3179988 (or 3179986 counting only the distinct ones).
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 2140251345012 its reverse (2105431520412), we get a palindrome (4245682865424).
The spelling of 2140251345012 in words is "two trillion, one hundred forty billion, two hundred fifty-one million, three hundred forty-five thousand, twelve".
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