Base | Representation |
---|---|
bin | 1001101110111010010000… |
… | …00100101110101101001111 |
3 | 2210210002222001021000101122 |
4 | 10313131020010232231033 |
5 | 10301131401444013112 |
6 | 113304230010431155 |
7 | 4336214031526643 |
oct | 467351004565517 |
9 | 83702861230348 |
10 | 21403031235407 |
11 | 6901a7a17a358 |
12 | 2498073a324bb |
13 | bc33b2bba513 |
14 | 53dcab280c23 |
15 | 271b1e1a9872 |
hex | 13774812eb4f |
21403031235407 has 2 divisors, whose sum is σ = 21403031235408. Its totient is φ = 21403031235406.
The previous prime is 21403031235367. The next prime is 21403031235437. The reversal of 21403031235407 is 70453213030412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21403031235407 - 230 = 21401957493583 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21403031235437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10701515617703 + 10701515617704.
It is an arithmetic number, because the mean of its divisors is an integer number (10701515617704).
Almost surely, 221403031235407 is an apocalyptic number.
21403031235407 is a deficient number, since it is larger than the sum of its proper divisors (1).
21403031235407 is an equidigital number, since it uses as much as digits as its factorization.
21403031235407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 35.
Adding to 21403031235407 its reverse (70453213030412), we get a palindrome (91856244265819).
The spelling of 21403031235407 in words is "twenty-one trillion, four hundred three billion, thirty-one million, two hundred thirty-five thousand, four hundred seven".
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