Search a number
-
+
214040132419 is a prime number
BaseRepresentation
bin1100011101010111001…
…0010011101101000011
3202110110211021022101211
43013111302103231003
512001323233214134
6242154554510551
721315054051451
oct3072562235503
9673424238354
10214040132419
1182857090523
1235595735457
131725103cc39
14a506a439d1
15587ad83764
hex31d5c93b43

214040132419 has 2 divisors, whose sum is σ = 214040132420. Its totient is φ = 214040132418.

The previous prime is 214040132417. The next prime is 214040132447. The reversal of 214040132419 is 914231040412.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 214040132419 - 21 = 214040132417 is a prime.

It is a super-2 number, since 2×2140401324192 (a number of 23 digits) contains 22 as substring.

Together with 214040132417, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (214040132417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107020066209 + 107020066210.

It is an arithmetic number, because the mean of its divisors is an integer number (107020066210).

Almost surely, 2214040132419 is an apocalyptic number.

214040132419 is a deficient number, since it is larger than the sum of its proper divisors (1).

214040132419 is an equidigital number, since it uses as much as digits as its factorization.

214040132419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

The spelling of 214040132419 in words is "two hundred fourteen billion, forty million, one hundred thirty-two thousand, four hundred nineteen".