Base | Representation |
---|---|
bin | 1100011101010111001… |
… | …0010011101101000011 |
3 | 202110110211021022101211 |
4 | 3013111302103231003 |
5 | 12001323233214134 |
6 | 242154554510551 |
7 | 21315054051451 |
oct | 3072562235503 |
9 | 673424238354 |
10 | 214040132419 |
11 | 82857090523 |
12 | 35595735457 |
13 | 1725103cc39 |
14 | a506a439d1 |
15 | 587ad83764 |
hex | 31d5c93b43 |
214040132419 has 2 divisors, whose sum is σ = 214040132420. Its totient is φ = 214040132418.
The previous prime is 214040132417. The next prime is 214040132447. The reversal of 214040132419 is 914231040412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 214040132419 - 21 = 214040132417 is a prime.
It is a super-2 number, since 2×2140401324192 (a number of 23 digits) contains 22 as substring.
Together with 214040132417, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (214040132417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107020066209 + 107020066210.
It is an arithmetic number, because the mean of its divisors is an integer number (107020066210).
Almost surely, 2214040132419 is an apocalyptic number.
214040132419 is a deficient number, since it is larger than the sum of its proper divisors (1).
214040132419 is an equidigital number, since it uses as much as digits as its factorization.
214040132419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 214040132419 in words is "two hundred fourteen billion, forty million, one hundred thirty-two thousand, four hundred nineteen".
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