Base | Representation |
---|---|
bin | 11111001001011011101… |
… | …100000110001111111101 |
3 | 21120121211101102121022011 |
4 | 133021123230012033331 |
5 | 240032101042444442 |
6 | 4315144554051221 |
7 | 310432620544414 |
oct | 37113354061775 |
9 | 7517741377264 |
10 | 2140431999997 |
11 | 755830076a15 |
12 | 2a69b6419b11 |
13 | 126ac3790065 |
14 | 7585161247b |
15 | 3aa26ad4117 |
hex | 1f25bb063fd |
2140431999997 has 2 divisors, whose sum is σ = 2140431999998. Its totient is φ = 2140431999996.
The previous prime is 2140431999983. The next prime is 2140432000009. The reversal of 2140431999997 is 7999991340412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1800349416441 + 340082583556 = 1341771^2 + 583166^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2140431999997 is a prime.
It is a super-2 number, since 2×21404319999972 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2140431999977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070215999998 + 1070215999999.
It is an arithmetic number, because the mean of its divisors is an integer number (1070215999999).
Almost surely, 22140431999997 is an apocalyptic number.
It is an amenable number.
2140431999997 is a deficient number, since it is larger than the sum of its proper divisors (1).
2140431999997 is an equidigital number, since it uses as much as digits as its factorization.
2140431999997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 39680928, while the sum is 67.
The spelling of 2140431999997 in words is "two trillion, one hundred forty billion, four hundred thirty-one million, nine hundred ninety-nine thousand, nine hundred ninety-seven".
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