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2140440433 is a prime number
BaseRepresentation
bin111111110010100…
…1000011101110001
312112011121122021121
41333211020131301
513340423043213
6552221022241
7104020305055
oct17745103561
95464548247
102140440433
119a924a63a
124b89b4981
132815aa001
141643b5c65
15c7da488d
hex7f948771

2140440433 has 2 divisors, whose sum is σ = 2140440434. Its totient is φ = 2140440432.

The previous prime is 2140440391. The next prime is 2140440443. The reversal of 2140440433 is 3340440412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1092170304 + 1048270129 = 33048^2 + 32377^2 .

It is a cyclic number.

It is not a de Polignac number, because 2140440433 - 229 = 1603569521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2140440398 and 2140440407.

It is not a weakly prime, because it can be changed into another prime (2140440443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070220216 + 1070220217.

It is an arithmetic number, because the mean of its divisors is an integer number (1070220217).

Almost surely, 22140440433 is an apocalyptic number.

It is an amenable number.

2140440433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2140440433 is an equidigital number, since it uses as much as digits as its factorization.

2140440433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 25.

The square root of 2140440433 is about 46264.8941747412. The cubic root of 2140440433 is about 1288.7471426828.

Adding to 2140440433 its reverse (3340440412), we get a palindrome (5480880845).

The spelling of 2140440433 in words is "two billion, one hundred forty million, four hundred forty thousand, four hundred thirty-three".