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2141030301413 is a prime number
BaseRepresentation
bin11111001001111111010…
…110011011111011100101
321120200101002020110112212
4133021333112123323211
5240034312224121123
64315324205453205
7310453504200413
oct37117726337345
97520332213485
102141030301413
117560078746a3
122a6b42871205
13126b8a712773
14758aac762b3
153aa5e3b8878
hex1f27f59bee5

2141030301413 has 2 divisors, whose sum is σ = 2141030301414. Its totient is φ = 2141030301412.

The previous prime is 2141030301401. The next prime is 2141030301491. The reversal of 2141030301413 is 3141030301412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2136838774849 + 4191526564 = 1461793^2 + 64742^2 .

It is a cyclic number.

It is not a de Polignac number, because 2141030301413 - 212 = 2141030297317 is a prime.

It is a super-3 number, since 3×21410303014133 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2141030307413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070515150706 + 1070515150707.

It is an arithmetic number, because the mean of its divisors is an integer number (1070515150707).

Almost surely, 22141030301413 is an apocalyptic number.

It is an amenable number.

2141030301413 is a deficient number, since it is larger than the sum of its proper divisors (1).

2141030301413 is an equidigital number, since it uses as much as digits as its factorization.

2141030301413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 2141030301413 its reverse (3141030301412), we get a palindrome (5282060602825).

Subtracting 2141030301413 from its reverse (3141030301412), we obtain a palindrome (999999999999).

The spelling of 2141030301413 in words is "two trillion, one hundred forty-one billion, thirty million, three hundred one thousand, four hundred thirteen".