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214104122014033 is a prime number
BaseRepresentation
bin110000101011101000000000…
…001000110011100101010001
31001002002011011101111100211001
4300223220000020303211101
5211030340220213422113
62035210024212422001
763045340510340326
oct6053500010634521
91032064141440731
10214104122014033
11622470592151a9
122001a991317901
139260c169c4804
143ac29a2748b4d
1519b4515eee7dd
hexc2ba00233951

214104122014033 has 2 divisors, whose sum is σ = 214104122014034. Its totient is φ = 214104122014032.

The previous prime is 214104122014001. The next prime is 214104122014099. The reversal of 214104122014033 is 330410221401412.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 154650414965904 + 59453707048129 = 12435852^2 + 7710623^2 .

It is a cyclic number.

It is not a de Polignac number, because 214104122014033 - 25 = 214104122014001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 214104122013992 and 214104122014010.

It is not a weakly prime, because it can be changed into another prime (214104122011033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107052061007016 + 107052061007017.

It is an arithmetic number, because the mean of its divisors is an integer number (107052061007017).

Almost surely, 2214104122014033 is an apocalyptic number.

It is an amenable number.

214104122014033 is a deficient number, since it is larger than the sum of its proper divisors (1).

214104122014033 is an equidigital number, since it uses as much as digits as its factorization.

214104122014033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 214104122014033 its reverse (330410221401412), we get a palindrome (544514343415445).

The spelling of 214104122014033 in words is "two hundred fourteen trillion, one hundred four billion, one hundred twenty-two million, fourteen thousand, thirty-three".