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21412171481 is a prime number
BaseRepresentation
bin10011111100010000…
…111100111011011001
32001021020210000100012
4103330100330323121
5322323003441411
613500413051305
71355420311631
oct237420747331
961236700305
1021412171481
119098681398
124196a86b35
13203312846c
141071a856c1
15854c1718b
hex4fc43ced9

21412171481 has 2 divisors, whose sum is σ = 21412171482. Its totient is φ = 21412171480.

The previous prime is 21412171463. The next prime is 21412171507. The reversal of 21412171481 is 18417121412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17529760000 + 3882411481 = 132400^2 + 62309^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21412171481 is a prime.

It is a super-2 number, since 2×214121714812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21412171981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10706085740 + 10706085741.

It is an arithmetic number, because the mean of its divisors is an integer number (10706085741).

Almost surely, 221412171481 is an apocalyptic number.

It is an amenable number.

21412171481 is a deficient number, since it is larger than the sum of its proper divisors (1).

21412171481 is an equidigital number, since it uses as much as digits as its factorization.

21412171481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3584, while the sum is 32.

Adding to 21412171481 its reverse (18417121412), we get a palindrome (39829292893).

The spelling of 21412171481 in words is "twenty-one billion, four hundred twelve million, one hundred seventy-one thousand, four hundred eighty-one".