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214125502142533 is a prime number
BaseRepresentation
bin110000101011111011111010…
…011111100001100001000101
31001002011012100101222102110011
4300223323322133201201011
5211031213012022030113
62035223521523030221
763050025361414432
oct6053737237414105
91032135311872404
10214125502142533
116225512a7a0193
1220022b5950b371
139262c432b1117
143ac3a3004cb89
1519b4d67ed763d
hexc2befa7e1845

214125502142533 has 2 divisors, whose sum is σ = 214125502142534. Its totient is φ = 214125502142532.

The previous prime is 214125502142509. The next prime is 214125502142561. The reversal of 214125502142533 is 335241205521412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 211018098237444 + 3107403905089 = 14526462^2 + 1762783^2 .

It is a cyclic number.

It is not a de Polignac number, because 214125502142533 - 29 = 214125502142021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (214125502140533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107062751071266 + 107062751071267.

It is an arithmetic number, because the mean of its divisors is an integer number (107062751071267).

Almost surely, 2214125502142533 is an apocalyptic number.

It is an amenable number.

214125502142533 is a deficient number, since it is larger than the sum of its proper divisors (1).

214125502142533 is an equidigital number, since it uses as much as digits as its factorization.

214125502142533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 214125502142533 its reverse (335241205521412), we get a palindrome (549366707663945).

The spelling of 214125502142533 in words is "two hundred fourteen trillion, one hundred twenty-five billion, five hundred two million, one hundred forty-two thousand, five hundred thirty-three".