Search a number
-
+
2141444113 is a prime number
BaseRepresentation
bin111111110100011…
…1101100000010001
312112020111122001221
41333220331200101
513341202202423
6552254325041
7104031655204
oct17750754021
95466448057
102141444113
119a9875726
124b91b9781
1328186bac3
1416459793b
15c8001e5d
hex7fa3d811

2141444113 has 2 divisors, whose sum is σ = 2141444114. Its totient is φ = 2141444112.

The previous prime is 2141444093. The next prime is 2141444131. The reversal of 2141444113 is 3114441412.

Together with next prime (2141444131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2076351489 + 65092624 = 45567^2 + 8068^2 .

It is a cyclic number.

It is not a de Polignac number, because 2141444113 - 213 = 2141435921 is a prime.

It is not a weakly prime, because it can be changed into another prime (2141444143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070722056 + 1070722057.

It is an arithmetic number, because the mean of its divisors is an integer number (1070722057).

Almost surely, 22141444113 is an apocalyptic number.

It is an amenable number.

2141444113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2141444113 is an equidigital number, since it uses as much as digits as its factorization.

2141444113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1536, while the sum is 25.

The square root of 2141444113 is about 46275.7400048881. The cubic root of 2141444113 is about 1288.9485478994.

Adding to 2141444113 its reverse (3114441412), we get a palindrome (5255885525).

The spelling of 2141444113 in words is "two billion, one hundred forty-one million, four hundred forty-four thousand, one hundred thirteen".