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214214124193 is a prime number
BaseRepresentation
bin1100011110000000101…
…0000010001010100001
3202110220221200000020121
43013200022002022201
512002202303433233
6242224132040241
721322266004216
oct3074012021241
9673827600217
10214214124193
118293631a083
1235623a63081
131727b0bc154
14a521bb5b0d
15588b2a192d
hex31e02822a1

214214124193 has 2 divisors, whose sum is σ = 214214124194. Its totient is φ = 214214124192.

The previous prime is 214214124169. The next prime is 214214124197. The reversal of 214214124193 is 391421412412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 201428620864 + 12785503329 = 448808^2 + 113073^2 .

It is a cyclic number.

It is not a de Polignac number, because 214214124193 - 233 = 205624189601 is a prime.

It is a super-3 number, since 3×2142141241933 (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (214214124197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107107062096 + 107107062097.

It is an arithmetic number, because the mean of its divisors is an integer number (107107062097).

Almost surely, 2214214124193 is an apocalyptic number.

It is an amenable number.

214214124193 is a deficient number, since it is larger than the sum of its proper divisors (1).

214214124193 is an equidigital number, since it uses as much as digits as its factorization.

214214124193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13824, while the sum is 34.

The spelling of 214214124193 in words is "two hundred fourteen billion, two hundred fourteen million, one hundred twenty-four thousand, one hundred ninety-three".