Base | Representation |
---|---|
bin | 110000101101010100000111… |
… | …110110000111111010110011 |
3 | 1001002111020211010210000201102 |
4 | 300231110013312013322303 |
5 | 211034241000123420230 |
6 | 2035335224113555015 |
7 | 63056620432306133 |
oct | 6055240766077263 |
9 | 1032436733700642 |
10 | 214220215451315 |
11 | 62291312a04997 |
12 | 20039390875a6b |
13 | 926bb58743ab8 |
14 | 3ac8456d00ac3 |
15 | 19b755d03a045 |
hex | c2d507d87eb3 |
214220215451315 has 64 divisors (see below), whose sum is σ = 277591661867520. Its totient is φ = 158123937300480.
The previous prime is 214220215451303. The next prime is 214220215451327. The reversal of 214220215451315 is 513154512022412.
It is an interprime number because it is at equal distance from previous prime (214220215451303) and next prime (214220215451327).
It is not a de Polignac number, because 214220215451315 - 210 = 214220215450291 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3433920614 + ... + 3433982996.
It is an arithmetic number, because the mean of its divisors is an integer number (4337369716680).
Almost surely, 2214220215451315 is an apocalyptic number.
214220215451315 is a deficient number, since it is larger than the sum of its proper divisors (63371446416205).
214220215451315 is a wasteful number, since it uses less digits than its factorization.
214220215451315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66432.
The product of its (nonzero) digits is 96000, while the sum is 38.
Adding to 214220215451315 its reverse (513154512022412), we get a palindrome (727374727473727).
The spelling of 214220215451315 in words is "two hundred fourteen trillion, two hundred twenty billion, two hundred fifteen million, four hundred fifty-one thousand, three hundred fifteen".
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