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214234323040433 is a prime number
BaseRepresentation
bin110000101101100001010000…
…101110010011100010110001
31001002112121020022200210211002
4300231201100232103202301
5211040003343144243213
62035345520032331345
763060630144655433
oct6055412056234261
91032477208623732
10214234323040433
11622972a2308453
12200400693a3b55
139270296422877
143ac8dd47c2653
1519b7ad6821658
hexc2d850b938b1

214234323040433 has 2 divisors, whose sum is σ = 214234323040434. Its totient is φ = 214234323040432.

The previous prime is 214234323040337. The next prime is 214234323040513. The reversal of 214234323040433 is 334040323432412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 213802211388529 + 432111651904 = 14621977^2 + 657352^2 .

It is a cyclic number.

It is not a de Polignac number, because 214234323040433 - 210 = 214234323039409 is a prime.

It is not a weakly prime, because it can be changed into another prime (214234323042433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107117161520216 + 107117161520217.

It is an arithmetic number, because the mean of its divisors is an integer number (107117161520217).

Almost surely, 2214234323040433 is an apocalyptic number.

It is an amenable number.

214234323040433 is a deficient number, since it is larger than the sum of its proper divisors (1).

214234323040433 is an equidigital number, since it uses as much as digits as its factorization.

214234323040433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 497664, while the sum is 38.

Adding to 214234323040433 its reverse (334040323432412), we get a palindrome (548274646472845).

The spelling of 214234323040433 in words is "two hundred fourteen trillion, two hundred thirty-four billion, three hundred twenty-three million, forty thousand, four hundred thirty-three".