Base | Representation |
---|---|
bin | 11111001011010001100… |
… | …110011000101011101001 |
3 | 21120210221020210021220221 |
4 | 133023101212120223221 |
5 | 240100124003322441 |
6 | 4320113142050041 |
7 | 310532631231502 |
oct | 37132146305351 |
9 | 7523836707827 |
10 | 2142410214121 |
11 | 756655793521 |
12 | 2a7268a19921 |
13 | 12704a57a168 |
14 | 7599c239ba9 |
15 | 3aae05e18d1 |
hex | 1f2d1998ae9 |
2142410214121 has 2 divisors, whose sum is σ = 2142410214122. Its totient is φ = 2142410214120.
The previous prime is 2142410214103. The next prime is 2142410214143. The reversal of 2142410214121 is 1214120142412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1095193645225 + 1047216568896 = 1046515^2 + 1023336^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2142410214121 is a prime.
It is not a weakly prime, because it can be changed into another prime (2142410514121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1071205107060 + 1071205107061.
It is an arithmetic number, because the mean of its divisors is an integer number (1071205107061).
Almost surely, 22142410214121 is an apocalyptic number.
It is an amenable number.
2142410214121 is a deficient number, since it is larger than the sum of its proper divisors (1).
2142410214121 is an equidigital number, since it uses as much as digits as its factorization.
2142410214121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1024, while the sum is 25.
Adding to 2142410214121 its reverse (1214120142412), we get a palindrome (3356530356533).
The spelling of 2142410214121 in words is "two trillion, one hundred forty-two billion, four hundred ten million, two hundred fourteen thousand, one hundred twenty-one".
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