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214322044244051 is a prime number
BaseRepresentation
bin110000101110110010111101…
…010100001001000001010011
31001002211222122202121122222102
4300232302331110021001103
5211042423021311302201
62035454104330231015
763100154023621652
oct6056627524110123
91032758582548872
10214322044244051
1162320517680047
122005506ab8546b
1392786360b4c03
143acd356bb1199
1519ba01cab926b
hexc2ecbd509053

214322044244051 has 2 divisors, whose sum is σ = 214322044244052. Its totient is φ = 214322044244050.

The previous prime is 214322044243999. The next prime is 214322044244093. The reversal of 214322044244051 is 150442440223412.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-214322044244051 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 214322044243996 and 214322044244014.

It is not a weakly prime, because it can be changed into another prime (214322044249051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107161022122025 + 107161022122026.

It is an arithmetic number, because the mean of its divisors is an integer number (107161022122026).

Almost surely, 2214322044244051 is an apocalyptic number.

214322044244051 is a deficient number, since it is larger than the sum of its proper divisors (1).

214322044244051 is an equidigital number, since it uses as much as digits as its factorization.

214322044244051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 245760, while the sum is 38.

Adding to 214322044244051 its reverse (150442440223412), we get a palindrome (364764484467463).

The spelling of 214322044244051 in words is "two hundred fourteen trillion, three hundred twenty-two billion, forty-four million, two hundred forty-four thousand, fifty-one".