Base | Representation |
---|---|
bin | 1100011110011110101… |
… | …1000001011100011011 |
3 | 202111020201220221220011 |
4 | 3013213223001130123 |
5 | 12002432043300012 |
6 | 242244434342351 |
7 | 21325356513511 |
oct | 3074753013433 |
9 | 674221827804 |
10 | 214340212507 |
11 | 829a050a0a3 |
12 | 3565a12a9b7 |
13 | 1729b268315 |
14 | a5348384b1 |
15 | 58973ab1a7 |
hex | 31e7ac171b |
214340212507 has 2 divisors, whose sum is σ = 214340212508. Its totient is φ = 214340212506.
The previous prime is 214340212469. The next prime is 214340212607. The reversal of 214340212507 is 705212043412.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-214340212507 is a prime.
It is not a weakly prime, because it can be changed into another prime (214340212607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107170106253 + 107170106254.
It is an arithmetic number, because the mean of its divisors is an integer number (107170106254).
Almost surely, 2214340212507 is an apocalyptic number.
214340212507 is a deficient number, since it is larger than the sum of its proper divisors (1).
214340212507 is an equidigital number, since it uses as much as digits as its factorization.
214340212507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 214340212507 its reverse (705212043412), we get a palindrome (919552255919).
The spelling of 214340212507 in words is "two hundred fourteen billion, three hundred forty million, two hundred twelve thousand, five hundred seven".
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