Base | Representation |
---|---|
bin | 1001101111111010100101… |
… | …01001010001101011000101 |
3 | 2210220102002222220000110201 |
4 | 10313331102221101223011 |
5 | 10302213114442420331 |
6 | 113332141040250501 |
7 | 4341545633130106 |
oct | 467752251215305 |
9 | 83812088800421 |
10 | 21437568326341 |
11 | 6915692497a12 |
12 | 24a28b2310a31 |
13 | bc67282447bb |
14 | 5418260cc3ad |
15 | 27299129ba61 |
hex | 137f52a51ac5 |
21437568326341 has 2 divisors, whose sum is σ = 21437568326342. Its totient is φ = 21437568326340.
The previous prime is 21437568326329. The next prime is 21437568326399. The reversal of 21437568326341 is 14362386573412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13277096250625 + 8160472075716 = 3643775^2 + 2856654^2 .
It is a cyclic number.
It is not a de Polignac number, because 21437568326341 - 29 = 21437568325829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21437568323341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10718784163170 + 10718784163171.
It is an arithmetic number, because the mean of its divisors is an integer number (10718784163171).
Almost surely, 221437568326341 is an apocalyptic number.
It is an amenable number.
21437568326341 is a deficient number, since it is larger than the sum of its proper divisors (1).
21437568326341 is an equidigital number, since it uses as much as digits as its factorization.
21437568326341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17418240, while the sum is 55.
The spelling of 21437568326341 in words is "twenty-one trillion, four hundred thirty-seven billion, five hundred sixty-eight million, three hundred twenty-six thousand, three hundred forty-one".
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