Base | Representation |
---|---|
bin | 11111001100110011001… |
… | …101100000000001000101 |
3 | 21120222011101022012122001 |
4 | 133030303031200001011 |
5 | 240112002222421413 |
6 | 4320543442305301 |
7 | 310621335043615 |
oct | 37146315400105 |
9 | 7528141265561 |
10 | 2144047857733 |
11 | 7573161363a1 |
12 | 2a7645358231 |
13 | 12724b933052 |
14 | 75ab592ca45 |
15 | 3ab892794dd |
hex | 1f333360045 |
2144047857733 has 2 divisors, whose sum is σ = 2144047857734. Its totient is φ = 2144047857732.
The previous prime is 2144047857709. The next prime is 2144047857737. The reversal of 2144047857733 is 3377587404412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1439467249284 + 704580608449 = 1199778^2 + 839393^2 .
It is a cyclic number.
It is not a de Polignac number, because 2144047857733 - 229 = 2143510986821 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2144047857737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072023928866 + 1072023928867.
It is an arithmetic number, because the mean of its divisors is an integer number (1072023928867).
Almost surely, 22144047857733 is an apocalyptic number.
It is an amenable number.
2144047857733 is a deficient number, since it is larger than the sum of its proper divisors (1).
2144047857733 is an equidigital number, since it uses as much as digits as its factorization.
2144047857733 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15805440, while the sum is 55.
The spelling of 2144047857733 in words is "two trillion, one hundred forty-four billion, forty-seven million, eight hundred fifty-seven thousand, seven hundred thirty-three".
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