Base | Representation |
---|---|
bin | 11111001100111000010… |
… | …000000000100000110111 |
3 | 21120222101021101110110211 |
4 | 133030320100000200313 |
5 | 240112140343314312 |
6 | 4321000102330251 |
7 | 310623412462216 |
oct | 37147020004067 |
9 | 7528337343424 |
10 | 2144132401207 |
11 | 757359930135 |
12 | 2a7669729987 |
13 | 1272632c4484 |
14 | 75ac2c5907d |
15 | 3ab918c93a7 |
hex | 1f338400837 |
2144132401207 has 2 divisors, whose sum is σ = 2144132401208. Its totient is φ = 2144132401206.
The previous prime is 2144132401129. The next prime is 2144132401289. The reversal of 2144132401207 is 7021042314412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2144132401207 - 231 = 2141984917559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2144132411207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072066200603 + 1072066200604.
It is an arithmetic number, because the mean of its divisors is an integer number (1072066200604).
Almost surely, 22144132401207 is an apocalyptic number.
2144132401207 is a deficient number, since it is larger than the sum of its proper divisors (1).
2144132401207 is an equidigital number, since it uses as much as digits as its factorization.
2144132401207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10752, while the sum is 31.
Adding to 2144132401207 its reverse (7021042314412), we get a palindrome (9165174715619).
The spelling of 2144132401207 in words is "two trillion, one hundred forty-four billion, one hundred thirty-two million, four hundred one thousand, two hundred seven".
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